Find an integer a such that a < √ 77 < a + 1.

How should I go about this? I think 76 or 78 is possible but I have to pick to 1 and I'm not sure which.

Guest Feb 27, 2021

#1**+2 **

Start by squaring the entire thing.

\(a^2 < 77 < (a+1)^2\)

Let's start with the first condition: a^2 < 77. From here, we know that a is equal to 8 or less.

Also, (8 + 1)^2 = 81, which works.

The integer a is **8.**

CubeyThePenguin Feb 27, 2021