+0  
 
0
56
2
avatar

Find an integer a such that a < √ 77 < a + 1.

How should I go about this? I think 76 or 78 is possible but I have to pick to 1 and I'm not sure which. 

 Feb 27, 2021
 #1
avatar+939 
+2

Start by squaring the entire thing.

 

\(a^2 < 77 < (a+1)^2\)

 

Let's start with the first condition: a^2 < 77. From here, we know that a is equal to 8 or less.

 

Also, (8 + 1)^2 = 81, which works.

 

The integer a is 8.

 Feb 27, 2021
 #2
avatar
0

Thank you so much! I can't believe I didn't think of squaring it!. 

Guest Feb 27, 2021

14 Online Users

avatar
avatar
avatar
avatar