Rewrite the inequality as
x^2 - 4x + y^2 - 6y ≤ 13
x^2 - 4x + 4 + y^2 - 6y + 9 = 13 + 4 + 9
(x-2)^2 + (y - 3)^2 ≤ 26
This is the area of a circle centred on x = 2, y = 3, with a radius of r = √26.
I'll leave you to find the area of a circle with radius r = √26.
+130 
