Let x and y be real numbers such that x−√x+6=√y+6−y.
Let m be the minimum value of x+y, and M be the maximum value of x+y. Enter the ordered pair (m, M).
Thanks for any tips, hints, or answers you provide, anything is appreciated.
I tried, but couldn't figure out the answer. :((
x - sqrt(x+6) = sqrt(y+6) - y
x + y = sqrt(y+6) + sqrt(x+6)
I'm not sure if this is true, but I feel like the maximum value of x+y would be when x = y.
So x = y = 3, making x + y = 6.
=^._.^=
+179 
