Inequality

Hey there, Guest!

We can go minus both sides of the expression by 20 and obtain the following,

$5x²+19x−4>05x²+19x−4>0$

$(5x−1)(x+4)>0(5x−1)(x+4)>0$

For the values that are not satisfied, we can take all the values between 1/5 and -4.

Values of x that are not satisfied =\([x:−4

which means that the answer to our problem is

$x=[0,−1,−2,−3].x=[0,−1,−2,−3].$

When counted, the number of elements, n(x), will give us 4.

And there we have our answer.

Hope this helped! :)

( ﾟдﾟ)つ Bye

5x^2  +  19x  + 16   > 20  - 13x            rearrange  as

5x^2  + 32x  - 4   >    0

See  the  graph here   : https://www.desmos.com/calculator/bc6p7e68v8

This  will be true  except  on  this  approx interval   ( -6.523, .123)

So   7  integer  values