For how many integer values of x is 5x^2 + 19x + 16 > 20 - 13x not satisfied?
+373 Hey there, Guest!
We can go minus both sides of the expression by 20 and obtain the following,
\(5x²+19x−4>05x²+19x−4>0\)
\((5x−1)(x+4)>0(5x−1)(x+4)>0\)
For the values that are not satisfied, we can take all the values between 1/5 and -4.
Values of x that are not satisfied =\([x:−4
which means that the answer to our problem is
\(x=[0,−1,−2,−3].x=[0,−1,−2,−3].\)
When counted, the number of elements, n(x), will give us 4.
And there we have our answer.
Hope this helped! :)
( ﾟдﾟ)つ Bye
