Find all integers n such that n^3 = (n - 1)^3 + 37.
I found two by brute force, i.e., n = 4 and n = –3
check n = 4
n3 = (n – 1)3 + 37
43 = 33 + 37
64 = 27 + 37
You can check n = –3 yourself, if you like.
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