+193 An engineer invested $10,000$inasix−monthsavingscertificatethatpaidasimpleannualinterestrateof$12%$.Aftersixmonths,sheinvestedthetotalvalueofherinvestmentinanothersix−monthcertificate.Aftersixmoremonths,theinvestmentwasworth$11,\!130$. If the annual interest rate of the second certificate is $r\%,$ then what is $r?$
+37167 *** edited ***
11 130 =(10000 + 10000*.12 /2 ) * (1+r/2)
where r is in decimal form %
r =10 %
