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If

 

\(\frac{\sin^2 3A}{\sin^2 A} - \frac{\cos^2 3A}{\cos^2 A} = 2\)

 

then find \(\cos2A\)

 Sep 1, 2020
 #1
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Hmm, this is an interesting problem. I believe maybe the use of trig identities would help but I'm not sure.

I doubt solving for A is necessary. Most likely I think that cos2A would pop up somehow. Not sure how though

 

Does anyone know how to do this? I also would like to know.
 

 Sep 1, 2020
 #2
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cos 2A = 12/13.

 Sep 1, 2020

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