We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
145
2
avatar+846 

A= (-1,0) B =(5,0)

 

for b:

{x^3/3 - 2x^2 -5x} between 5 and -1

i subbed in 5 and subtracted the value i got from subbing in -1 but i got -36

(125/3 - 50 -25) - (-1/3 -2 +5)

what went wrong??

 Jan 8, 2019
 #1
avatar+18439 
+2

If you want a positive area    Start with the value of -1   and subtract the value of  5        =36    (or just take the absolute value of your result)

 

Note: Areas UNDER the x- axis are generally given a negative sign (so you got it correct)

 Jan 8, 2019
edited by Guest  Jan 8, 2019
edited by Guest  Jan 8, 2019
 #2
avatar+846 
+1

ok thank you very much

YEEEEEET  Jan 8, 2019

10 Online Users

avatar