+0  
 
0
618
2
avatar+845 

A= (-1,0) B =(5,0)

 

for b:

{x^3/3 - 2x^2 -5x} between 5 and -1

i subbed in 5 and subtracted the value i got from subbing in -1 but i got -36

(125/3 - 50 -25) - (-1/3 -2 +5)

what went wrong??

 Jan 8, 2019
 #1
avatar+36916 
0

If you want a positive area    Start with the value of -1   and subtract the value of  5        =36    (or just take the absolute value of your result)

 

Note: Areas UNDER the x- axis are generally given a negative sign (so you got it correct)

 Jan 8, 2019
edited by Guest  Jan 8, 2019
edited by Guest  Jan 8, 2019
 #2
avatar+845 
+1

ok thank you very much

YEEEEEET  Jan 8, 2019

4 Online Users

avatar
avatar