Interior & Exterior Angles of Polygons

So we know in a pentagon there are in total 540 degrees.
Then, 7x+4+5x+4+4x+9+9x-6+4x+1 = 540 = 29x + 12

540-12 =  528

528/29 = x

Let me know if you have any questions about the way I solved.

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the sum of the interior angles of a pentagon: (5-2)*180 = 540

adding up all the degrees to make an equation, you get:

7x+4+5x+4+4x+9+9x-6+4x+1 = 540

simplifying that (by combining the like terms and adding the constants), you get:

29x+12 = 540

29x = 528

x = 528/29 = 18 6/29

hope this helped! please correct me if i am wrong:)

interior angles of a pentagon = 540deg

so we set up the equation (7x+4)+(5x+4)+(4x+9)+(9x-6)+(4x+1)=540

combine like terms and simplify and divide both sides by 29 to get 528/29