+0  
 
+6
79
7
avatar+549 

Let  \(x, y\) and \(z\) be positive real numbers such that \(x+y+z=1.\) Find the maximum value of \(x^3y^2z\).

 Jul 22, 2020
 #1
avatar
0

say x=1 and y and z=0 so 1*0*0=0 so answer is 0!

 

 

coolcoolcool

 Jul 22, 2020
edited by Guest  Jul 22, 2020
 #2
avatar+549 
+4

that was wrong

please double-check your answer (i can't risk getting this problem wrong wink)

amazingxin777  Jul 22, 2020
 #3
avatar
-1

????????

 

sadsadsad( i am on peralgebra not intimated algrebra!)

 Jul 22, 2020
 #4
avatar
-1

You get the maximum when x = y = z = 1/3.  The maximum value is then (1/3)^6 = 1/729.

 Jul 22, 2020
 #5
avatar+549 
+4

surprise

that was wrong as well but it's ok it is really hard problem

amazingxin777  Jul 22, 2020
 #6
avatar+1130 
+1

well it could be [biggest number],-[biggest number],1

 Jul 22, 2020
edited by jimkey17  Jul 22, 2020
 #7
avatar+1130 
+1

so it is [biggest number]^5

jimkey17  Jul 22, 2020

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