Let f(x) = 7x + 5 and g(x) = x + 1. If h(x) = f(g(x)) , then what is the inverse of h(x)?
+526 f(x) = 7x + 5
and g(x) = x + 1
⇒ \(h(x)=f(g(x))\)
\(=f(x+1)\)
\(=7x+7+5\)
\(=7x+12\)
In order to find \(h^{-1}(x)\)
Let \(y=h(x)\)
\(y=7x+12\)
\(x= {y-12\over 7}\)
⇒ \(h^{-1}(x) = {x-12 \over 7}\)
Thus, inverse of h(x) is \({x-12 \over 7}\)
~Amy
