Suppose that $g(x) = f^{-1}(x)$. If g(-15) = 0, g(0) = 4, g(3) = 9, and g(9) = 3, what is f(f(9))?
Because f(x) is the inverse of \( f^{-1}(x)\), and g(x) = \( f^{-1}(x)\), f(x) is the inverse of g(x). Thus, if g(15) = 0, g(0) = 4, g(3) = 9, g(9) = 3, then f(0) = 15, f(4) = 0, f(9) = 3, f(3) = 9.
Thus, f(f(9)) = f(3) = 9