+36915 So x = k y^3 but y = c/z we can combine these by substituting in for y
x = k (c/z^3) = kc/z^3 we can combine the constants k and c in to one constant k
x = k/z^3 when z = 12 x = 3 solve for k
3 = k /(12^3) so k = 5184
when z= 75 x = 5184/75^3 = 5184/421875 = 192/15625
+36915 Read your question......you left off the really important relationship between y and z.
+36915 So x = k y^3 but y = c/z we can combine these by substituting in for y
x = k (c/z^3) = kc/z^3 we can combine the constants k and c in to one constant k
x = k/z^3 when z = 12 x = 3 solve for k
3 = k /(12^3) so k = 5184
when z= 75 x = 5184/75^3 = 5184/421875 = 192/15625
