#3**+2 **

So x = k y^3 but y = c/z we can combine these by substituting in for y

x = k (c/z^3) = kc/z^3 we can combine the constants k and c in to one constant k

x = k/z^3 when z = 12 x = 3 solve for k

3 = k /(12^3) so k = 5184

when z= 75 x = 5184/75^3 = 5184/421875 = 192/15625

ElectricPavlov Feb 12, 2019

#1**+1 **

Read your question......you left off the really important relationship between y and z.

ElectricPavlov Feb 11, 2019

#3**+2 **

Best Answer

So x = k y^3 but y = c/z we can combine these by substituting in for y

x = k (c/z^3) = kc/z^3 we can combine the constants k and c in to one constant k

x = k/z^3 when z = 12 x = 3 solve for k

3 = k /(12^3) so k = 5184

when z= 75 x = 5184/75^3 = 5184/421875 = 192/15625

ElectricPavlov
Feb 12, 2019