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 Inverse proportionality question

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z is inversely proportional to x. When x=3, z=2.
Show that z=c*y^n, where c and n are numbers and c > 0.
(You must find the values of c and n.)

 

I've managed to get that z=6/x but I'm stuck at that point, where does c and n come from. Is this some kind of simultanious equation I'm missing? Not exactly sure what to do would appreciate help! :)

 Mar 2, 2015

Best Answer 

 #1
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+10

I am not sure either, but looking at the information;

The constant of proportion is 6, I assume therefore the C* is 6.

When z=2 and c*=6 y^n must equal 1/3, resulting in y^n=1/3

n must therefore = -1

What do you think?

 Mar 2, 2015

2+0 Answers

 #1
avatar
+10
Best Answer

I am not sure either, but looking at the information;

The constant of proportion is 6, I assume therefore the C* is 6.

When z=2 and c*=6 y^n must equal 1/3, resulting in y^n=1/3

n must therefore = -1

What do you think?

Guest Mar 2, 2015
 #2
avatar+118673 
+5

Maybe i am wrong but this question doesn't make sense to me.

c and n are numbers, they don't phase me, but where did y suddenly appear from?

Are you sure there is not something missing or changed from the original question?

 Mar 3, 2015

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