Find the modular inverse of 27, modulo 29. Express your answer as an integer from 0 to 28, inclusive.
Thanks guest.
14 is correct. I think guest did it with a calculator.
This is fine but I will give a non-calculator answer
Find N such that 27*N (mod29) = 1
\(27\equiv-2 \mod 29\\ 30\equiv 1 \mod 29\\ -2*-15 = 30 \equiv 1 \mod29\\ -15\equiv 29-15 \mod29 \equiv 14 \mod29\\ so\\ 27*14=1 \mod29\\ \text{So 14 is the modular inverse of 27 (mod 29)}\)