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Rounded to the nearest quarter year, how long will it take an investment to quadruple if it earns 8% compounded semi-annually?

 

Any help would be greatly appreciated with calculations.

 

Thanks

 Dec 19, 2015

Best Answer 

 #1
avatar
+5

Rounded to the nearest quarter year, how long will it take an investment to quadruple if it earns 8% compounded semi-annually?

 

Any help would be greatly appreciated with calculations.

 

Thanks

 

This is very simple and easy problem to solve. He is basically asking: How long would it take for $1 to become $4 @8% S.A.

The first thing you should do is to convert 8% from S.A. compound to quarterly compound, which comes to 7.92% comp. quarterly. Then you would solve for n, or number of periods. If you do it right, you should get: 70.69 quarters, or rounded to the nearest quarter=71 quarters. or 70.69/4=17 years and 3 quarters(rounded to neatest quarter).

The formula you use is the same PV formula that you know. The only difficulty you might have is solving for n. You have to use Logs to do that.

 Dec 19, 2015
 #1
avatar
+5
Best Answer

Rounded to the nearest quarter year, how long will it take an investment to quadruple if it earns 8% compounded semi-annually?

 

Any help would be greatly appreciated with calculations.

 

Thanks

 

This is very simple and easy problem to solve. He is basically asking: How long would it take for $1 to become $4 @8% S.A.

The first thing you should do is to convert 8% from S.A. compound to quarterly compound, which comes to 7.92% comp. quarterly. Then you would solve for n, or number of periods. If you do it right, you should get: 70.69 quarters, or rounded to the nearest quarter=71 quarters. or 70.69/4=17 years and 3 quarters(rounded to neatest quarter).

The formula you use is the same PV formula that you know. The only difficulty you might have is solving for n. You have to use Logs to do that.

Guest Dec 19, 2015
 #2
avatar+129850 
+5

4A = A( 1 + .08/2)^(2n)       divide both sides by A

 

4 = ( 1 + .08/2)^(2n)           take the log of both sides

 

log [4]   =  log (1.04)^(2n)     and we can wrtie

 

log [4]  =  (2n) log (1.04)      divide both sides by 2log(1.04)

 

log [4]  / [2log(1.04)]  = n   =   about 17.67 years  ≈  17 + 2/3   years

 

 

 

cool cool cool

 Dec 19, 2015

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