+870 Read the following calculations:
$$\\a=b\\
a\times a= a\times b\\
a^2=ab\\
a^2+a^2=a^2+ab\\
2a^2=a^2+ab\\
2a^2-2ab=a^2+ab-2ab\\
2a^2-2ab=a^2-ab\\
2a^2-2ab=1a^2-1ab\\
2(a^2-ab)=1(a^2-ab)\\
2=1$$
Can you spot the miscalculation ?
+870 For those who haven't understood, the miscalculation is on the penultimate line :
Since a²=ab, a²-ab=0;
And in the 9th line, I divided each side by a²-ab, so I divided by 0; and as you must now, the division by 0 is impossible.
a=b
axa=axb
a^2=ab
a^2+a^2=a^2+ab
a^4=a^2+ab
2a^2-2ab=a^2-ab
2a^2-2ab=1a^2-1ab
the correct answer is to this part is: 2a^2-2ab=a^2-ab
so the final answer is a=square root of ab
+870 For those who haven't understood, the miscalculation is on the penultimate line :
Since a²=ab, a²-ab=0;
And in the 9th line, I divided each side by a²-ab, so I divided by 0; and as you must now, the division by 0 is impossible.
