+870 $$\\
\mathbb{R}\textup{ is the set of real numbers. For any number }x\textup{ in }\mathbb{R:}\\
x^2\geq 0\\
(x^2)^{1/2}\geq 0^{1/2}\\
x^{2\times1/2}\geq 0\\
x^1\geq 0\\
x\geq 0$$
+118608 Thanks EinstienJr,
did you already know the problem with the question?
If you did you really should say so up front because otherwise, one day you will ask a 'real' question and I will think,
I won't answer that because I am buy and I expect that he/she already knows the answer. :)
+118608 There is a bit of a problem here Einstein,
I have been struggling with exactly the same problem on complex number questions lately.
$$\\(x^2)^{1/2}>0\qquad true\\\\$$
consider
$$\\x^2=36\\
\sqrt{x^2}=\pm 6\\
$I put the square root in so both answers are valid$\\$$
so
$$\\(x^2)^{1/2}\ge0\\
\pm x \ge0\\
$either $x\ge0\;\;or\;\;-x\ge 0\\
$either $x\ge0\;\;or\;\;x\le 0\\
$Hence x is any real number $$$
+118608 Thanks EinstienJr,
did you already know the problem with the question?
If you did you really should say so up front because otherwise, one day you will ask a 'real' question and I will think,
I won't answer that because I am buy and I expect that he/she already knows the answer. :)
