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Is the best way to approximate e by using Limits or by a infinite sum with factorials?

 

lim (n-> inf) (1+1/n)^n

 

Or

 

\(\sum_{n=0}^{inf}(1/n!)\)

 Sep 24, 2016
edited by Guest  Sep 24, 2016

Best Answer 

 #1
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+5

Assuming that you are looking for a numerical value,write out the series   for e^x

and then put  x=1 .The series converges very quickly so you don't need to take many terms to get an accurate value. 

 

that is e^x = 1 + x + (x^2)/2!  + (x^3)/3!   etc etc  ....  and just plug in  x=1

 Sep 24, 2016
 #1
avatar
+5
Best Answer

Assuming that you are looking for a numerical value,write out the series   for e^x

and then put  x=1 .The series converges very quickly so you don't need to take many terms to get an accurate value. 

 

that is e^x = 1 + x + (x^2)/2!  + (x^3)/3!   etc etc  ....  and just plug in  x=1

Guest Sep 24, 2016
 #2
avatar
+5

If you use this expansion, it will give you 50% more digits:

(1 + 1/10^100)^(10^100.5)

 Sep 24, 2016

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