I have the equation:


this equation was derived from solving the logistic growth equation:

\(\frac{dP}{dt}=rP\big(1-\frac{P}{K}\big) \)


r is the rate of growth = 1.13

K is the maximum population = 10,000


I've been asked to change the growth rate to:

\(r = 0.83 + \frac{0.3}{1+0.3t}\)


My question is,

Do I have to solve the entire logistic growth equation again, that is,

or can I just substituted r into the derived equation and rearrage, that is,

I wanted to get some clarification as I've tried doing both process with a simpler equation, however the answer still get quite complex and I'm not sure If I've done it correctly.


Thank you.

vest4R  Mar 29, 2018
edited by vest4R  Mar 29, 2018

In my opinion I don't think it matters if \(r = 0.83 + \frac{0.3}{1+0.3t}\) is substituted staight into p(t)


but I'm not overly confident about that.

vest4R  Mar 29, 2018

8 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.