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# Is there another way to prove this besides induction? Help asap

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$$1^3+2^3+3^3+...+n^3=(\frac{n(n+1)}{2})^2$$

Dec 14, 2022

#1
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The sum of the cubes of the first n natural numbers is given by the formula: ((n(n+1)/2)^2 = (n^2(n+1)^2)/4 Therefore, the sum of the cubes of the first n natural numbers is ((n^2(n+1)^2)/4).

Dec 14, 2022
#2
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Have a look at https://mathschallenge.net/library/number/sum_of_cubes

Dec 14, 2022