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A motorcycle is depreciating at 19% per year, every year. A student's $21,000 motorcycle depreciating at this rate can be modeled by the equation V(t) = 21,000(0.81)^t. What is an equivalent equation for this vehicle as a monthly depreciation and, using this equation, what is the motorcycle worth (rounded to the nearest ten dollar) 4 years after purchase?

i got v(t)=21,000(0.9826)^12t,$9,040

 Feb 20, 2016

Best Answer 

 #1
avatar+2498 
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you can check it by youself put in term s of t  4:

21000(0.9826)^48 = 9042.8174786606693723

21000*0.81^4 = 9039.81141

 

but i think:

\(V(m)=21,000(0.81)^{\frac{m}{12}} \\ \text{m-represent month}\)

 Feb 20, 2016

1+0 Answers

 #1
avatar+2498 
+10
Best Answer

you can check it by youself put in term s of t  4:

21000(0.9826)^48 = 9042.8174786606693723

21000*0.81^4 = 9039.81141

 

but i think:

\(V(m)=21,000(0.81)^{\frac{m}{12}} \\ \text{m-represent month}\)

Solveit Feb 20, 2016

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