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The lengths of the sides of isosceles triangle ABC are 3x + 62, 7x + 30, and 5x + 60 feet. What is the least possible number of feet in the perimeter of ABC?

 Nov 15, 2021
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174.

 

Consider the 3 possible choices of equivalent side lengths: 3x+62=5x+60, 7x+30=5x+60, and 3x+62=7x+30.

 

By solving for all three, we get the following results:

3x+62 = 5x+60, x= 1

3x+62 = 7x+30, x = 8

5x+60 = 7x + 30, x = 15. 

 

These show that the least possible perimeter sees x = 1, so we can solve (3x1 +62) + (5x1+60) + (7x1+30) = 174.

 Nov 16, 2021

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