+0  
 
0
73
2
avatar

A parabola opening up or down has vertex (0, – 6) and passes through (12,6). Write its equation in vertex form.

 Mar 17, 2023
 #1
avatar
0

Vertex form is (as follows): y=a(x-h)^2+k, where k is the y-value of the vertex and h is the x-value of the vertex. This means that all we need to find is a.

Let's write what we have in vertex: a(x-0)^2-6 OR ax^2-6Now, if we have the point (12,6) on our graph, we need to substitute the values to find a. Steps:

 

  1. 6 = 144a - 6
  2. 144a = 12
  3. a=1/12

So finally, our answer is 1/12(x-0)^2 - 6 (Some people simplify down to (x) but it depends on whomever uses it.)

 

 

P.S. What grade level is this?

 Mar 17, 2023
 #2
avatar
0

their iq

Guest Mar 18, 2023

2 Online Users

avatar