A parabola opening up or down has vertex (0, – 6) and passes through (12,6). Write its equation in vertex form.

Guest Mar 17, 2023

#1**0 **

Vertex form is (as follows): ** y=a(x-h)^2+k**, where

Let's write what we have in vertex: * a(x-0)^2-6 OR ax^2-6. *Now, if we have the point (12,6) on our graph, we need to substitute the values to find

- 6 = 144a - 6
- 144a = 12
- a=1/12

So finally, our answer is * 1/12(x-0)^2 - 6* (

P.S. What grade level is this?

Guest Mar 17, 2023