A parabola opening up or down has vertex (0, – 6) and passes through (12,6). Write its equation in vertex form.
Vertex form is (as follows): y=a(x-h)^2+k, where k is the y-value of the vertex and h is the x-value of the vertex. This means that all we need to find is a.
Let's write what we have in vertex: a(x-0)^2-6 OR ax^2-6. Now, if we have the point (12,6) on our graph, we need to substitute the values to find a. Steps:
So finally, our answer is 1/12(x-0)^2 - 6 (Some people simplify down to (x) but it depends on whomever uses it.)
P.S. What grade level is this?
