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# jade threw a die 100 times and recorded these results. she calculated the relative frequency of the result 5 was 0.23. 'that is a lot higher

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jade threw a die 100 times and recorded these results. she calculated the relative frequency of the result 5 was 0.23. 'that is a lot higher than i would have thought', she said. do you agree? breifly comment, justifying your answer using suitable calculations.

Jul 9, 2015

#1
+107500
+5

Well, I am no stats expert but... this is a binomial distribution.

Each time the die is rolled there is a 1/6 = 0.16 repeater chance of rolling a 5.

You are asking if 23 fives is a probable outcome.

I am going to jump over to a binomial calculator

http://stattrek.com/online-calculator/binomial.aspx

I put in the info and it spits out some cumulative probabilities.  (Maybe you use tables for this?)

Anway it tells me that     \$\$p(x\ge 23)=0.0605\$\$

This means that if you throw a fair die 100 times and count the number of 5s

and you do this a great many times, then you will get 23 or more fives  approx 6% of the time.

SO, at a five percent significance level this is not significant.

Jul 9, 2015

#1
+107500
+5

Well, I am no stats expert but... this is a binomial distribution.

Each time the die is rolled there is a 1/6 = 0.16 repeater chance of rolling a 5.

You are asking if 23 fives is a probable outcome.

I am going to jump over to a binomial calculator

http://stattrek.com/online-calculator/binomial.aspx

I put in the info and it spits out some cumulative probabilities.  (Maybe you use tables for this?)

Anway it tells me that     \$\$p(x\ge 23)=0.0605\$\$

This means that if you throw a fair die 100 times and count the number of 5s

and you do this a great many times, then you will get 23 or more fives  approx 6% of the time.

SO, at a five percent significance level this is not significant.

Melody Jul 9, 2015