Jamire is observing potential relationships between one having no trust in government and no widows peak. Assume a survey of 100 randomly selected persons revealed the following data:
The probability of selecting a person with a trust in government is 0.572.
The probability of selecting a person with a widows peak is 0.319.
The probability of selecting a person with a trust in government and a widows peak is 0.182.
If you were to choose a person at random from the sample, determine the probability they have no trust in government and no widows peak.
For simplicity....let's suppose that instead of 100 people in the survey, let 1000 people be in the survey
Then 572 had trust in the government
And 319 had a widow's peak
And the number who had trust in gov and a widow's peak = 182
So...those who only had trust in gov =572 - 182 = 390
And those that only had a widow's peak = 319 - 182 = 137
So....those that had no trust in gov and no widow's peak =
1000 - ( 390 + 182 +137) =
1000 - 709 = 291
So....as the guest said...P ( no trust in gov and no widow's peak) = 291 / 1000 = .291
Thank you so much, CPhill, for helping me with a step by step solution for this problem! Probability is one of the few subjects that I don't understand in math. I have other similar math problems, but with a different approach. I don't know if I should solve them the same way as this here, so it's something to look at for more teaching.