+73 Jamire is observing potential relationships between one having no trust in government and no widows peak. Assume a survey of 100 randomly selected persons revealed the following data:
The probability of selecting a person with a trust in government is 0.572.
The probability of selecting a person with a widows peak is 0.319.
The probability of selecting a person with a trust in government and a widows peak is 0.182.
If you were to choose a person at random from the sample, determine the probability they have no trust in government and no widows peak.
+129849 For simplicity....let's suppose that instead of 100 people in the survey, let 1000 people be in the survey
Then 572 had trust in the government
And 319 had a widow's peak
And the number who had trust in gov and a widow's peak = 182
So...those who only had trust in gov =572 - 182 = 390
And those that only had a widow's peak = 319 - 182 = 137
So....those that had no trust in gov and no widow's peak =
1000 - ( 390 + 182 +137) =
1000 - 709 = 291
So....as the guest said...P ( no trust in gov and no widow's peak) = 291 / 1000 = .291
+73 Thank you so much, CPhill, for helping me with a step by step solution for this problem! Probability is one of the few subjects that I don't understand in math. I have other similar math problems, but with a different approach. I don't know if I should solve them the same way as this here, so it's something to look at for more teaching.
