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avatar+1195 

Jamire is observing potential relationships between one having no trust in government and no widows peak. Assume a survey of 100 randomly selected persons revealed the following data:

 

The probability of selecting a person with a trust in government is 0.572.

The probability of selecting a person with a widows peak is 0.319.

The probability of selecting a person with a trust in government and a widows peak is 0.182.

 

If you were to choose a person at random from the sample, determine the probability they have no trust in government and no widows peak.

 Dec 21, 2020
 #1
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+1

I think it is is .291   using a Venn diagram .....

 Dec 21, 2020
 #2
avatar+117724 
+2

For simplicity....let's suppose that instead of  100 people  in the  survey, let 1000  people be in the  survey

 

Then  572  had trust in the government

And 319 had a widow's peak

And the number who had trust in gov and a widow's peak = 182

 

So...those  who only had trust in  gov  =572 - 182  = 390

And those that only had a widow's peak =  319 - 182  = 137

 

So....those  that  had no trust in gov and  no widow's peak  =

 

1000 -  ( 390 + 182 +137)   = 

 

1000 - 709   =  291

 

So....as the guest said...P ( no trust in gov and  no widow's peak) =  291 / 1000  =  .291

 

 

cool cool cool

 Dec 21, 2020
 #3
avatar+1195 
+2

Thank you so much, CPhill, for helping me with a step by step solution for this problem! Probability is one of the few subjects that I don't understand in math. I have other similar math problems, but with a different approach. I don't know if I should solve them the same way as this here, so it's something to look at for more teaching.

GAMEMASTERX40  Dec 21, 2020
 #4
avatar+117724 
+1

Well, GM.....the dirty little secret is that EVERYONE on this site sometimes struggles with probabiity....I'm not  very  good at it, either, so I usually qualify my answers with a "Here's what I think"  disclaimer.....(or words to that effect )

 

 

cool cool cool

CPhill  Dec 22, 2020

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