+279 Jason designed an arch made of wrought iron for the top of a mall entrance. The 11 segments between the two concentric circles are each 1.25 m long. Find the total length of wrought iron used to make the structure. Round the answer to the nearest meter.
+118608 Do you mean that the radius of the big one is 7.5m across and the radius of the little one is 5m accross
$$\begin{array}{rll}
Area &=& 0.5[\pi\times 7.5^2 - \pi\times 5^2]\\\\
&=& 0.5\pi[56.25-25]\\\\
&=& 0.5\pi\times 31.25\\\\
&=& 0.5\pi\times 31.25\\\\
&=& 49.087\\\\
&=& 49\:m^2
\end{array}$$
+118608 Natasza, do you mean that the arch is a half the area between 2 concentric cicles where the difference in the 2 radii is 1.25m? the question is quite confusing. What has the 11 sebments got to do with anything?
Like this ? 
+279 Yes, Melody! Sorry for no picture. The document I Got this From Is on Microsoft Word :(
At the floor of The Arch, It Is 15 Meters.
:)
+118608 Do you mean that the radius of the big one is 7.5m across and the radius of the little one is 5m accross
$$\begin{array}{rll}
Area &=& 0.5[\pi\times 7.5^2 - \pi\times 5^2]\\\\
&=& 0.5\pi[56.25-25]\\\\
&=& 0.5\pi\times 31.25\\\\
&=& 0.5\pi\times 31.25\\\\
&=& 49.087\\\\
&=& 49\:m^2
\end{array}$$
