A square park of an area 4225 sq. m has to be fenced. The fencing will require the use of a wire that can enclose the park 4 times and each circuit of the wire would be 5 % greater than the perimeter of the park. What length of the wire is needed for this?

Guest Oct 3, 2019

#1**+2 **

sqrt (4225) = 65 = side of the square

So....the perimeter of the park = 4 * 65 = 260 ft

So......the length of wire needed is

First perimeter + Second perimeter + Third perimeter + Fourth perimeter =

260 + 260(1.05) + 260(1.05)^2 + 260(1.05)^3 ≈ 1120.6 ft

CPhill Oct 3, 2019