juan is thinking of an irrational number that is greater than 5 but less than 6. which number matches this description? a. square root of 28 b. square root of 37 c. ^3 square root of 228 d. ^3 square root of 224
Well
$$5^2 = 25$$
$$6^2 = 36$$
Which means
$$\sqrt{25} = 5$$
$$\sqrt{36} = 6$$
Hence for any number
$$5 < c < 6$$
$$\sqrt{25} < \sqrt{c} < \sqrt{36}$$
Therefore the only correct answer is
$$a.) \sqrt{28}$$
