Just A Fun Question

I don't really no but what grade is this fun math question??

Let the student's age  = S

Let the difference in their ages = D

So...

The student's age now minus the difference in their ages  = 3....and....when the student is the teachers age, the teacher will be 63....so.....the teacher's age now must be (S + D) .....and in D years.....the student will be S + D years old  and the teacher will be (S + D) + D  years old........so.... 

S - D  = 3

(S + D) + D  =  66   simplify

S - D  = 3

S + 2D  = 63       subtract the first equation from the second

3D  = 60

D  = 20

S - D  = 3

S = 20 + 3   =  23

And the teacher's age  =  23 + 20  =  43

Nice job CPhill and just wondering are you a teacher??

Another way:

Let the current teacher's age = T
Let the current student's age = S
T - S = S - 3.............(1)
T - S =63 - T............(2), solve for S, T
S = 23 - Student's age
T = 43 - Teacher's age.