+0  
 
-1
109
4
avatar+364 

So.. I made this question to test my self, I know the answer but... i have no idea how to solve it...

2ny^2=2n^2y-96

how do I find n and y

 Jun 17, 2020
edited by TacoBell  Jun 17, 2020
 #1
avatar
0

You have to use Newton-Raphson iteration method. You may have to look it up.
y =- 6 and n = - 4
y = 2 and n = - 4
y = - 6 and n = - 2
y = 4  and  n = - 2
y = 2  and  n = 6
y = 4  and  n = 6

 Jun 17, 2020
 #2
avatar+307 
+1

First divide both sides by 2.

\(ny^2=n^2y-48\)

Then move all the variables to one side.

\(n^2y-ny^2=48\)

\(ny(n-y)=48\)

I factorized 48 and used trial and error to find

\(ny=12\)

\(n-y=4\)

Solve and find \(n=6, y=2\)

 Jun 17, 2020
 #3
avatar+364 
-1

not quite, y= 4 yes but n=6 but it helped 

TacoBell  Jun 17, 2020
edited by TacoBell  Jun 17, 2020
 #4
avatar+21953 
0

With your problem, the factoring can result in more than one correct answer, but the process shown is good.

The "Newton-Raphson iteration method" has nothing to do with this problem.

 Jun 17, 2020

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