+129852 Prove that if a tangent line is drawn to the parabola y = x^2 at the point x = a.......then the line will have a y-intercept of ( 0, -a^2 )
+37146 Parabola y = x^2
when x= a y = a^2
Slope = 2x (derivative of x^2)
y=mx+b yields a^2 = 2a(a) + b
a^2 = 2a^2 + b
0 = a^2 + b
b= -a^2
so y = mx + b becomes y = 2x(x) - a^2 When x = 0 y = - a^2
Yah?
+37146 Parabola y = x^2
when x= a y = a^2
Slope = 2x (derivative of x^2)
y=mx+b yields a^2 = 2a(a) + b
a^2 = 2a^2 + b
0 = a^2 + b
b= -a^2
so y = mx + b becomes y = 2x(x) - a^2 When x = 0 y = - a^2
Yah?
