Not quite, Solveit.......remember that the "long" car can only fit in one of three slots....and for each of these, the other four cars can be arranged in 4! ways.......does that give you a hint???
Solveit:
Remember: 1 car has a choice of only 3 spots. It can park in any of those 3 and there will be 4 parking slots remaining. So, it has 3 choices.
The next car can park in any of 4 slots.
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, 3 slots.
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, 2 slots.
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, 1 slot.
So, we have: 3 X 4 X 3 X 2 X1=3 X 4!=72 Different ways that the 5 cars can be parked.