Math __TOPIC(and apparently problem)__ question...

Right, so my question is how do you get the domain of a function?

I know this differs from the traditional one problem, but I think that giving me help on a whole topic will be better, so I can solve it on my own. Thank you in advance to anyone who helps

Deep Thanks, ππππππππππ

\(tommarvoloriddle\)

EDIT:

The part I am having trouble understanding is how would you do it to a polynomial fraction function...

Like how would you find the domains such things?

EDIT(again):

How would you solve for the domain

\(f(x)=\frac{x^2-4}{x-4}\)

Just help me through the steps plsssssssssss

tommarvoloriddle Jul 3, 2019

edited by
tommarvoloriddle
Jul 3, 2019

edited by tommarvoloriddle Jul 3, 2019

edited by tommarvoloriddle Jul 3, 2019

edited by tommarvoloriddle Jul 3, 2019

edited by tommarvoloriddle Jul 3, 2019

edited by tommarvoloriddle Jul 3, 2019

edited by tommarvoloriddle Jul 3, 2019

edited by tommarvoloriddle Jul 3, 2019

edited by tommarvoloriddle Jul 3, 2019

edited by tommarvoloriddle Jul 3, 2019

edited by tommarvoloriddle Jul 3, 2019

#1**+2 **

Assuming your function is of the form y=f(x)

then the domain is just the set of all possible x values.

With a normal polynomial that is all real x

I am not sure what you mean by a poynomial fraction function.

I suppose if there is an x on the bottom of a fraction then there will be restrictions because it is not possible to divide bt 0.

Melody Jul 3, 2019

#3**+9 **

that was actually my hw question and I don't know how to solve it... Can you help?

tommarvoloriddle
Jul 3, 2019

#4**+1 **

Well the bdenominator cannot be 0 so x cannot be 4. x can be anything else.

So the domain is \(x \in Real \;\;\;where \;\;x\ne4\)

This can be written in a number of formats but they all mean the same.

The actual fuction is f(x)=x+4 where x not equal 4

It is a straight line with a hole at (4,8)

Melody
Jul 3, 2019