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avatar+1718 

Math TOPIC(and apparently problem) question...

 

Right, so my question is how do you get the domain of a function?

I know this differs from the traditional one problem, but I think that giving me help on a whole topic will be better, so I can solve it on my own. Thank you in advance to anyone who helps

 

Deep Thanks, πŸ˜€πŸ˜ƒπŸ˜„πŸ˜πŸ˜ŠπŸ˜‡πŸ˜ŒπŸ˜‹πŸ˜œπŸ˜Ž

\(tommarvoloriddle\)

 

EDIT:

 

The part I am having trouble understanding is how would you do it to a polynomial fraction function...

 

Like how would you find the domains such things?

 

 

EDIT(again):

 

How would you solve for the domain 

\(f(x)=\frac{x^2-4}{x-4}\)

 

Just help me through the steps plsssssssssss

 Jul 3, 2019
edited by tommarvoloriddle  Jul 3, 2019
edited by tommarvoloriddle  Jul 3, 2019
edited by tommarvoloriddle  Jul 3, 2019
edited by tommarvoloriddle  Jul 3, 2019
edited by tommarvoloriddle  Jul 3, 2019
edited by tommarvoloriddle  Jul 3, 2019
 #1
avatar+105881 
+2

Assuming your function is of the form  y=f(x)

then the domain is just the set of all possible x values.

With a normal polynomial that is all real x

 

I am not sure what you mean by a poynomial fraction function.

I suppose if there is an x on the bottom of a fraction then there will be restrictions because it is not possible to divide bt 0.

 Jul 3, 2019
 #2
avatar+1718 
+9

I mean like: \(f(x)=\frac{x^2-4}{x-4}\)

tommarvoloriddle  Jul 3, 2019
edited by tommarvoloriddle  Jul 3, 2019
 #3
avatar+1718 
+9

that was actually my hw question and I don't know how to solve it... Can you help?

tommarvoloriddle  Jul 3, 2019
 #4
avatar+105881 
+1

Well the bdenominator cannot be 0 so x cannot be 4.  x can be anything else.

So the domain is       \(x \in Real \;\;\;where \;\;x\ne4\)

 

This can be written in a number of formats but they all mean the same.

 

The actual fuction is  f(x)=x+4 where  x not equal 4

 

It is a straight line with a hole at   (4,8)

Melody  Jul 3, 2019
 #5
avatar+1718 
+8

:O Thank You Melody

 

πŸ˜€πŸ˜ƒπŸ˜„πŸ˜πŸ˜ŠπŸ˜‡πŸ˜ŒπŸ˜‹πŸ˜›πŸ˜œπŸ˜Ž

tommarvoloriddle  Jul 3, 2019

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