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# L hopital rule

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Nov 26, 2014

#7
+28029
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But I'm willing to be set straight!

NB: The last expression still reduces to e-5, so L'Hopital's rule still works of course, but I see it as an unnecessarily complicated approach here.

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Nov 27, 2014

#1
+28029
+10

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Nov 26, 2014
#2
+1832
0

Can you solve it by taking the lin in the both sides

Nov 26, 2014
#3
+28029
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xvxvxv wrote: Can you solve it by taking the lin in the both sides

I don't understand what you are asking!

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Nov 26, 2014
#4
+101771
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Thanks Alan - I didn't know that 'by definition' bit.

Actually you haven't used L'hopitals rule though ?

Nov 27, 2014
#5
+28029
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In this case L'Hopital's rule makes things ten times worse!

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Nov 27, 2014
#6
+1832
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But we didn't study this method

We always try to simplify it ti give us zero by zero or infinity by infinity then using l hopital rule

Nov 27, 2014
#7
+28029
+15

But I'm willing to be set straight!

NB: The last expression still reduces to e-5, so L'Hopital's rule still works of course, but I see it as an unnecessarily complicated approach here.

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Alan Nov 27, 2014
#8
+101771
+10

Hi Alan,

Yes I did not think that L'Hopital's rule helped either.

I was just pointing out that the question requested it and it was not used.  That is all.   :)

Nov 27, 2014
#9
+1832
0

Nice thank you Alan.

First what do you mean by

" As t tend to infinity t+2 tends to t "

Nov 27, 2014
#10
+28029
+10

Compare 5/(t+2) with 5/t for various values of t:

t        5/(t+2)                  5/t

1          1.67                       5

10        0.42                       0.5

100     0.049                      0.05

1000   0.00499                  0.005

...

106    4.99999*10-6           5*10-6

1010  4.999999999*10-10  5*10-10

You can see that as t gets bigger, 5/(t+2) becomes closer and closer to 5/t, so it's in this sense that t+2 becomes more and more like t as t tends to infinity.

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Nov 27, 2014
#11
+1832
+5

nice

thank you

Nov 27, 2014