xvxvxv wrote: Can you solve it by taking the lin in the both sides
I don't understand what you are asking!
Thanks Alan - I didn't know that 'by definition' bit.
Actually you haven't used L'hopitals rule though ?
But we didn't study this method
We always try to simplify it ti give us zero by zero or infinity by infinity then using l hopital rule
But I'm willing to be set straight!
NB: The last expression still reduces to e-5, so L'Hopital's rule still works of course, but I see it as an unnecessarily complicated approach here.
Yes I did not think that L'Hopital's rule helped either.
I was just pointing out that the question requested it and it was not used. That is all. :)
Nice thank you Alan.
But can you please explain to me your method
First what do you mean by
" As t tend to infinity t+2 tends to t "
Compare 5/(t+2) with 5/t for various values of t:
t 5/(t+2) 5/t
1 1.67 5
10 0.42 0.5
100 0.049 0.05
1000 0.00499 0.005
106 4.99999*10-6 5*10-6
1010 4.999999999*10-10 5*10-10
You can see that as t gets bigger, 5/(t+2) becomes closer and closer to 5/t, so it's in this sense that t+2 becomes more and more like t as t tends to infinity.