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A 16-foot ladder leans against the side of a building. the top of the ladder touches the side of the building at 12 feet above the ground. how far away from the base of the building is the bottom of the ladder?

Guest Aug 3, 2017

#1**0 **

A 16-foot ladder leans against the side of a building. the top of the ladder touches the side of the building at 12 feet above the ground. how far away from the base of the building is the bottom of the ladder?

Use Pythagoras's theorem to solve the unknown side:

Let the base of this triangle = B, So you have:

B^2 + 12^2 = 16^2

B^2 + 144 = 256 subtract 144 from both sides

B^2 = 256 - 144

B^2 = 112 take the square root of both sides

**B = 10.583 - feet - the distance from the base of the building to the ladder.**

Guest Aug 3, 2017