Subtract seven more than twice a number from the square of one-third of the number to get to zero.
Again please don't just give me the answer. Please just the sentence. Thanks in advance!!!
Subtract seven more than twice a number from the square of one-third of the number to get to zero.
Let N be the number.....
"Seven more than twice a number" ⇒ 2N + 7 (1)
"Square of 1/3 of the number" ⇒ (N/3)^2 (2)
So....we are subtracting (1) from (2) and this = 0 .....so....
(N / 3)^2 - [ 2N + 7] = 0