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avatar+666 

Subtract seven more than twice a number from the square of one-third of the number to get to zero.

 

Again please don't just give me the answer. Please just the sentence. Thanks in advance!!!

 Dec 13, 2018
 #1
avatar+100513 
+2

Subtract seven more than twice a number from the square of one-third of the number to get to zero.

 

Let N be the number.....

 

"Seven more than twice a number"  ⇒     2N + 7      (1)

 

"Square of 1/3 of the number" ⇒   (N/3)^2         (2)

 

So....we are subtracting  (1) from (2)   and this = 0        .....so....

 

 

(N / 3)^2  -  [ 2N + 7]  =   0

 

 

cool cool cool

 Dec 13, 2018
 #3
avatar+666 
0

Thanks CPhill once again!!

 

smileysmiley

ilovepuppies1880  Dec 13, 2018
 #5
avatar+100513 
0

Glad to help, ILP.....!!!!

 

 

cool cool cool

CPhill  Dec 13, 2018
 #2
avatar+18324 
+1

(1/3 x)^2  -(7+ 2x) = 0

 Dec 13, 2018
edited by Guest  Dec 13, 2018
 #4
avatar+666 
0

Thanks Guest!

 

smileysmiley

ilovepuppies1880  Dec 13, 2018
 #6
avatar+18324 
+1

Anytime !    

ElectricPavlov  Dec 13, 2018
 #7
avatar+100513 
0

"Guest"   =   EP  "Incognito"

 

 

cool cool cool

CPhill  Dec 13, 2018
 #8
avatar+666 
0

Hahah wow nice fast one EP

ilovepuppies1880  Dec 13, 2018
 #9
avatar+18324 
+1

Sneaky that way.....but mostly, I often forget to sign in ! cheeky

ElectricPavlov  Dec 13, 2018
 #10
avatar+666 
0

Haha ok

ilovepuppies1880  Dec 14, 2018

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