Subtract seven more than twice a number from the square of one-third of the number to get to zero.

Again please don't just give me the answer. Please just the sentence. Thanks in advance!!!

ilovepuppies1880 Dec 13, 2018

#1**+2 **

Subtract seven more than twice a number from the square of one-third of the number to get to zero.

Let N be the number.....

"Seven more than twice a number" ⇒ 2N + 7 (1)

"Square of 1/3 of the number" ⇒ (N/3)^2 (2)

So....we are subtracting (1) from (2) and this = 0 .....so....

(N / 3)^2 - [ 2N + 7] = 0

CPhill Dec 13, 2018