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1.

 

2.

 

 

Walking for exercise and running for exercise not independent events because P(A|B)=P(A) andP(B|A)=P(B) .

Walking for exercise and running for exercise are independent events because P(A|B)≠P(A) and P(B|A)≠P(B) .

Walking for exercise and running for exercise are independent events because P(A|B)=P(A)P(A|B)=P(A) andP(B|A)=P(B) .

Walking for exercise and running for exercise are not independent events because P(A|B)≠P(A) andP(B|A)≠P(B) 

 

3.

The yearly attendance at a ballpark is shown in the table.

Which answer describes the average rate of change from Year 2 to Year 5?

 

Attendance increased by an average of 35,400 people per year from Year 2 to Year 5.

Attendance decreased by an average of 35,400 people per year from Year 2 to Year 5.

Attendance increased by an average of 11,800 people per year from Year 2 to Year 5.

Attendance decreased by an average of 11,800 people per year from Year 2 to Year 5.

4.

which intervals is the function positive? Choose each correct answer

5.

Use a graphing calculator or other technology to answer the question.

Which quadratic regression equation best fits the data set?

 

 

Thanks so much, its all a lot in one knowledge thing, just really need help

 May 27, 2019
 #1
avatar+8829 
+2

1.

 

probabillity that number of heads in trial is_0__=__4 / 80__=__0.05
probability that number of heads in trial is1=8 / 80=0.10
probability that number of heads in trial is2=36 / 80=0.45
probability that number of heads in trial is3=20 / 80=0.25
probability that number of heads in trial is4=12 / 80=0.15
 May 27, 2019
 #2
avatar+8829 
+3

3.

The yearly attendance at a ballpark is shown in the table.

Which answer describes the average rate of change from Year 2 to Year 5?

average rate of change from year  2  to year  5   =   \( \frac{\text{333,700 people - 298,300 people}}{\text{5 years - 2 years}}\)

 

average rate of change from year  2  to year  5   =   \( \frac{\text{35,400 people}}{\text{3 years}}\)

 

average rate of change from year  2  to year  5   =   \( \frac{\text{11,800 people}}{\text{1 years}}\)

 

average rate of change from year  2  to year  5   =   11,800 people per year

 May 27, 2019
 #3
avatar+8829 
+3

4.

y  is positive when  x  is in the interval  (-∞, -2)

 

y  is positive when  x  is in the interval  (0, 4)

 May 27, 2019

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