1.

2.

Walking for exercise and running for exercise not independent events because P(A|B)=P(A) andP(B|A)=P(B) .

Walking for exercise and running for exercise are independent events because P(A|B)≠P(A) and P(B|A)≠P(B) .

Walking for exercise and running for exercise are independent events because P(A|B)=P(A)P(A|B)=P(A) andP(B|A)=P(B) .

Walking for exercise and running for exercise are not independent events because P(A|B)≠P(A) andP(B|A)≠P(B)

3.

The yearly attendance at a ballpark is shown in the table.

Which answer describes the average rate of change from Year 2 to Year 5?

Attendance increased by an average of 35,400 people per year from Year 2 to Year 5.

Attendance decreased by an average of 35,400 people per year from Year 2 to Year 5.

Attendance increased by an average of 11,800 people per year from Year 2 to Year 5.

Attendance decreased by an average of 11,800 people per year from Year 2 to Year 5.

4.

which intervals is the function positive? Choose each correct answer

5.

Use a graphing calculator or other technology to answer the question.

Which quadratic regression equation best fits the data set?

Thanks so much, its all a lot in one knowledge thing, just really need help

PhoenixForever May 27, 2019

#1**+2 **

**1.**

probabillity that number of heads in trial is_ | 0 | __=__ | 4 / 80 | __=__ | 0.05 |

probability that number of heads in trial is | 1 | = | 8 / 80 | = | 0.10 |

probability that number of heads in trial is | 2 | = | 36 / 80 | = | 0.45 |

probability that number of heads in trial is | 3 | = | 20 / 80 | = | 0.25 |

probability that number of heads in trial is | 4 | = | 12 / 80 | = | 0.15 |

hectictar May 27, 2019

#2**+3 **

**3.**

The yearly attendance at a ballpark is shown in the table.

Which answer describes the average rate of change from Year 2 to Year 5?

average rate of change from year 2 to year 5 = \( \frac{\text{333,700 people - 298,300 people}}{\text{5 years - 2 years}}\)

average rate of change from year 2 to year 5 = \( \frac{\text{35,400 people}}{\text{3 years}}\)

average rate of change from year 2 to year 5 = \( \frac{\text{11,800 people}}{\text{1 years}}\)

average rate of change from year 2 to year 5 = 11,800 people per year

hectictar May 27, 2019