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# Last few problems I need help with ASAP please!

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1.

2.

Walking for exercise and running for exercise not independent events because P(A|B)=P(A) andP(B|A)=P(B) .

Walking for exercise and running for exercise are independent events because P(A|B)≠P(A) and P(B|A)≠P(B) .

Walking for exercise and running for exercise are independent events because P(A|B)=P(A)P(A|B)=P(A) andP(B|A)=P(B) .

Walking for exercise and running for exercise are not independent events because P(A|B)≠P(A) andP(B|A)≠P(B)

3.

The yearly attendance at a ballpark is shown in the table.

Which answer describes the average rate of change from Year 2 to Year 5?

Attendance increased by an average of 35,400 people per year from Year 2 to Year 5.

Attendance decreased by an average of 35,400 people per year from Year 2 to Year 5.

Attendance increased by an average of 11,800 people per year from Year 2 to Year 5.

Attendance decreased by an average of 11,800 people per year from Year 2 to Year 5.

4.

which intervals is the function positive? Choose each correct answer

5.

Use a graphing calculator or other technology to answer the question.

Which quadratic regression equation best fits the data set?

Thanks so much, its all a lot in one knowledge thing, just really need help

May 27, 2019

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1.

 probabillity that number of heads in trial is_ 0 __=__ 4 / 80 __=__ 0.05 probability that number of heads in trial is 1 = 8 / 80 = 0.1 probability that number of heads in trial is 2 = 36 / 80 = 0.45 probability that number of heads in trial is 3 = 20 / 80 = 0.25 probability that number of heads in trial is 4 = 12 / 80 = 0.15
May 27, 2019
#2
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3.

The yearly attendance at a ballpark is shown in the table.

Which answer describes the average rate of change from Year 2 to Year 5?

average rate of change from year  2  to year  5   =   $$\frac{\text{333,700 people - 298,300 people}}{\text{5 years - 2 years}}$$

average rate of change from year  2  to year  5   =   $$\frac{\text{35,400 people}}{\text{3 years}}$$

average rate of change from year  2  to year  5   =   $$\frac{\text{11,800 people}}{\text{1 years}}$$

average rate of change from year  2  to year  5   =   11,800 people per year

May 27, 2019
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4.

y  is positive when  x  is in the interval  (-∞, -2)

y  is positive when  x  is in the interval  (0, 4)

May 27, 2019