#1**+1 **

Let's write

y = 5^(x + 1) we wnat to get x by itself and then "swap" x and y

In log form we have

log _{5 }(y) = x + 1 subtract 1 form both sides

log _{5} (y) - 1 = x "swap" x and y

log _{5} (x) - 1 = y this is the inverse and we can write

g(x) = log _{5} (x) - 1 [ this goes in the first blank ]

The graph of the exponential function is a shift of 1 unit to the left

The graph of the log function is a shift 1 unit down from its parent function

CPhill Nov 18, 2019

#2**+1 **

for the first 1 theres two options that are very similar, would you need the parenetheses around (x+1) or no?

jjennylove
Nov 18, 2019