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# Last question

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+1489

I am unsure with this one as well. Thanks for helping me!

Nov 18, 2019

#1
+106515
+1

Let's write

y = 5^(x + 1)           we wnat to get x by itself and then "swap"  x and y

In log form we have

log 5 (y)  = x + 1       subtract 1 form  both sides

log 5 (y) - 1  = x     "swap" x and y

log 5 (x)  - 1  = y       this is the inverse   and we can write

g(x)  = log 5 (x)  - 1    [ this goes in the first blank ]

The graph of the exponential function is a shift of  1 unit   to the left

The graph of the log function  is a shift  1 unit down from its parent function

Nov 18, 2019
#2
+1489
+1

for the first 1 theres two options that are very similar, would you need the parenetheses around (x+1) or no?

jjennylove  Nov 18, 2019
#3
+106515
+1

No  parentheses  around the "1"

g(x) = log 5  ( x - 1)  is a shift of the parnet unit to the right by one unit

g(x)  =log 5 (x)   - 1   is a shift of  the parent function down one unit

We want the second one.....

CPhill  Nov 18, 2019