LaTeX Form (Part 4)

Question 2

What is this shape?

Triangular prism

If you cut it anywhere, parallel to the front triangle side.  What will be the shape of the cross section?

A triangle

What is the area of the front triangle? (Show working)

6.4*8.2 = 52.48 . As we are finding the area of a triangle we do the formula L*W/2.   52.48/2 = 26.24cm^2

If this was made of mm^3 blocks (some would need to be cut up) How many cubes would be needed to cover the front face? 

???

How many rows of block triangles would you need to make the whole shape?

15.7

What is the volume of this shape? (Show working)

Formula = (L*H)/2*W

(8.2*6.4)/2=26.24cm^2

26.24*15.7= 411.968cm^2

I don't get the 'mm/cm^3' bit...

Continuing from the last post.

I'm doing good in Angles so far i wasn't really getting the protractor bit because i didn't know where to start i get it now.

In school we're doing expanding brackets, but i totally get it.

Hi MG,

You like answering algebra questions but sometimes it is very obvious that you do not understand the basic concepts  behind them.

Here are a set of adding like terms video clips.

I think this address is for the middle one in the series.  The early ones are probably too easy.

Take a look and see if you can get anything out of it :)  

Stop the video sometimes and try to answer the questions yourself before the answer is given :)

https://www.khanacademy.org/math/algebra-basics/core-algebra-expressions/core-algebra-manipulating-expressions/v/combining-like-terms-2

I'll watch the video and answer the questions.

AFTER VIDEO : Seems pretty easy it's simplifying, it looks like I mess up most of time i because i either rush it / Mist-type and not check.

The video was good.

You know MG

I don't think that you are as good at basic algebra as you think you are.  Is it worth trying those same questions again?

Ok.                                              

Hi MG here is a question for you.  :))

1) Tell me what area is and then...

2) Tell me the approximate area of each of these shapes.  

$$\\$An area is the calculation of the inside of the shape$\\\\
$I'll answer each question from left to right starting from rectangle$\\\\
$Each square is 1cm^2\;\mathbf{approximately}\\\\
1)\;5cm^2\\\\
2)\;5cm^2\\\\
3)\;5cm^2\\\\
4)\;5cm^2\\\\
5)\;5cm^2\\\\
6)\;5cm^2\quad\\\\$$

$$\\$(This one was slightly harder, but i saw if you look at the row of the shape, which is 4 squares, it's half shaded diagnolly so approximately it's four, the bottom square on the left is fully shaded apart from the corner which is slightly not shaded approximately a square, the one to the left of the square i was just talking about matched perfectly with the square to left the left of that. As for the triangle at the bottom of the shape those two squares make 1. 2+1+1+1 =5)\\\\
This is the shape on the bottom right corner.$$$

That is great MG.

So you obviously do understand that area is how many squares fit inside a 2 dimensional shape :)

Please copy and paste the questions so that it all stays together with your answers :)

Try very hard to answer the exact question that I have asked :) This is one reason why students lose marks.  They do not answer the exact question that is asked :)

Question 1

Look at this shape.  This is made up of cubic blocks  Each side is 1cm. 

What is the area of the front face? (include units)

How many cubes are in the front row?

How many rows of blocks are there counting back from the front row?

What is the volume of the prism?

Write a sentence as to why.

Question 2

What is this shape?

If you cut it anywhere, parallel to the front triangle side.  What will be the shape of the cross section?

What is the area of the front triangle? (Show working)

If this was made of mm^3 blocks (some would need to be cut up) How many cubes would be needed to cover the front face? 

How many rows of block triangles would you need to make the whole shape?

What is the volume of this shape? (Show working)

How many mm^3 are there in a cm^3?      You have to show your working.

How many cm^3 are there in the above shape?  Please do it 2 ways and check that your answers are the same. :)

I don't mind points!

Question 1

Look at this shape.  This is made up of cubic blocks  Each side is 1cm. 

What is the area of the front face? (include units) 

36cm^2

How many cubes are in the front row?

30

How many rows of blocks are there counting back from the front row?

3 rows

What is the volume of the prism?

108cm

Write a sentence as to why.

The formula is (L*H)*W

Thanks for having a good shot at these questions MG  

Question 1     4 out of 5 for you :)

Look at this shape.  This is made up of cubic blocks  Each side is 1cm. 

What is the area of the front face? (include units) 

36cm^2           Correct

How many cubes are in the front row?

30                  

No there are 36 cubes, the front of the cubes makes up the area that you wrote correctly above

How many rows of blocks are there counting back from the front row?

3 rows                Correct

What is the volume of the prism?

108cm             No it is 108cm^3

Write a sentence as to why.

The formula is (L*H)*W     

Mmm yes I guess so but I wanted you to say that there are 36 blocks in the first row and there are 3 rows so that makes 36+36+36 = 108 cm cubes

or if you prefer, it makes  36*3=108 cm cubed

Question 2

What is this shape?          Triangular prism       Correct

If you cut it anywhere, parallel to the front triangle side.  What will be the shape of the cross section?

A triangle      Correct

What is the area of the front triangle? (Show working)

6.4*8.2 = 52.48 . As we are finding the area of a triangle we do the formula L*W/2.   52.48/2 = 26.24cm^2

Yes that is correct

If this was made of mm^3 blocks (some would need to be cut up) How many cubes would be needed to cover the front face?     ???     Well there are 10 mm in a cm so you have to change the dimensions to mm and then work out the area of the front face.   I will leve you to do this.  :)

How many rows of block triangles would you need to make the whole shape?    15.7

if the blocks were 1cm^3 then you would be correct but they are 1mm^3  so you better answer again :)

What is the volume of this shape? (Show working)

Formula = (L*H)/2*W

(8.2*6.4)/2=26.24cm^2

26.24*15.7= 411.968cm^2             No:  Volume is not measured in cm^2

How many mm^3 are there in a cm^3?      You have to show your working.  I don't get the 'mm/cm^3' bit...

If there are 10 mm in a cm ?   Hoe many mm^3 are there in a cm^3?    Try thinking on it :)

Try to re-answer the ones you got wrong please MG  :)

I'll post more questions for you soon :))

Dumb mistake meant 36. >.<

If this was made of mm^3 blocks (some would need to be cut up) How many cubes would be needed to cover the front face?     ???     Well there are 10 mm in a cm so you have to change the dimensions to mm and then work out the area of the front face.   I will leave you to do this.  :)

I knew that there was 10mm in a cm but the power bit puzzles me.

would it 36cm^2*10=

360cm^2

How many rows of block triangles would you need to make the whole shape?    15.7

if the blocks were 1cm^3 then you would be correct but they are 1mm^3  so you better answer again :)

Would it be the same by multiplying by 10.   15.7cm*10=

570mm^3

What is the volume of this shape? (Show working)

Formula = (L*H)/2*W

(8.2*6.4)/2=26.24cm^2

26.24*15.7= 411.968cm^2             No:  Volume is not measured in cm^2

411.968^3

Sorry Melody. But I'm really stuck. I haven't done this yet only one lesson in class about 2 months ago.

I haven't seen ^3 yet...

The only reason i know what I'm doing so far, is because of the video you gave me.

Sorry I have taken so long to answer MG   

Here are some videos on volume that you might like to look at 

They are ordered from easiest to hardest :)

1)     https://www.youtube.com/watch?v=jgpwhYLm6uo

2)     https://www.youtube.com/watch?v=nZxldpVaQLo

3)     https://www.youtube.com/watch?v=u2TRb5nUnwE

4)     https://www.youtube.com/watch?v=I3vYW5SUp3Y

It's alright. :D

Hi MathsGod1,

Let me know how you get on with those videos :)