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find the LCM of (x-3)^2, x^(2)-9, and (x + 3)^2 and (x - 1)^2.

 Feb 14, 2021
 #1
avatar+530 
+1

First, factor the second term:

x2 - 9 is a difference in squares so it equals (x + 3)(x - 3)

This means the terms are now:

(x - 3)2 , (x + 3)(x - 3) , (x + 3)2 , and (x - 1)2

 

Now the factors of these terms are: (x - 3) , (x + 3) , and (x - 1)

The least common multiple (LCM) is just the term with the largest power that holds these factors. 
This means the LCM is (x - 3)2(x + 3)2(x - 1)2, which is also your answer :)

 Feb 14, 2021
 #2
avatar+74 
+1

Answer: (x-1)^2*(x-3)^2*(x+3)^2

 

https://www.polymathlove.com/special-polynomials/least-common-measure/lcm-of-polynomials-calculator.html#c=lcm_algstepslcm&v230=%2528x%2520-%25201%2529%255E2%252C%2520%2528x%2520%2B%25203%2529%255E2%252C%2520%2520x%255E%25282%2529-9%252C%2520%2528x-3%2529%255E2

 Feb 14, 2021

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