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The figure is made up of a piece of wire. It consists of four semicircles and a straight line. The radius of the largest semicircle is 42 inches. The diameter of the smallest semicircle is 21 inches. The other two semicircles are each of radius 21 inches. Calculate the length of the wire. Use 22/7 as an approximation for pi.

 

This is the figure:

mathcalc  Jun 2, 2015

Best Answer 

 #1
avatar+78551 
+5

Putting eveything in terms of a radius.....the smallest semi-circle has a diameter of 21, so the radius = 10.5

 

And the perimeter of each semi-circle is given by .... pi * r

 

So, the length of the wire is given by:

 

(22/7) (42 + 2(21) + 10.5) =  297 inches

 

 

CPhill  Jun 2, 2015
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1+0 Answers

 #1
avatar+78551 
+5
Best Answer

Putting eveything in terms of a radius.....the smallest semi-circle has a diameter of 21, so the radius = 10.5

 

And the perimeter of each semi-circle is given by .... pi * r

 

So, the length of the wire is given by:

 

(22/7) (42 + 2(21) + 10.5) =  297 inches

 

 

CPhill  Jun 2, 2015

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