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Let a, b, and c be integers that satisfy 2a+3b=52, 3b+c=41, and bc=60. Find a+b+ c.

 Apr 14, 2021
 #1
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I need help with this ASAP. Please help 

 Apr 14, 2021
 #2
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Let's start by finding 3b+c=41

From the problem "bc=60", we know that b and c are both divisors of 60. We can use this to help us solve this.

These are the divisors of 60 if you need them:

1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, and 60.

 

Before looking at what B and C are I want you to try to figure it out...

Ok, "b" is 12, and "c" is 5laugh

Now we just have to figure out "a"


"2a+3b=52"

We already know b is 12 so we can rewrite the problem like this

2a + 36 (because 12 times 3 is 36) = 52

Now we just subtract 36 from both sides and we get

2a = 16

Now we just have to divide each side by 2 and...

 "a" is 8!
 


"Find a+b+ c."

Finally, we add up all our numbers

8 + 12 + 5 = 25! surprise

Hope this helped! laugh

 Apr 15, 2021

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