Let ABC be a right triangle such that B is a right angle. A circle with diameter of BC meets side AC at D. If the area of ABC is 150 and AC = 40 then what is BD?
+284 
If we draw the diagram, we can see that BD is the height of triangle ABC. This gives us: A = 1/2(AC)*(BD).
Plugging in the numbers we get: 150 = 1/2*(25)*(BD).
We can solve this to get BD = 12.
Hope this helped!
Caffeine :)
+1641 Let ABC be a right triangle such that B is a right angle. A circle with a diameter of BC meets side AC at D. If the area of ABC is 150 and AC = 40 then what is BD?
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Area of Δ ABC: A = 150 u2
The base of a triangle ABC: AC = 40 units
BD = 2A / AC = 300 / 40 BD = 7.5 units 
