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# Let f(x)=3x^4-7x^3+2x^2-bx+1. For what value of b is f(1)=1

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Let f(x)=3x^4-7x^3+2x^2-bx+1. For what value of b is f(1)=1

Jun 2, 2020

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First, you substitute 1 in for x, and you will get $$3\cdot1^4-7\cdot1^3+2\cdot1^2-b+1=1$$

Simplify.$$3-7+2-b+1=1$$

$$-1-b=1$$

$$b=-2$$

Jul 20, 2020