Which has \(1+2\sqrt{3}, 3-\sqrt{2}\) as roots, and such that \(f(0) = -154\)
The conjugates will also be roots
So.....the polynomial is
P(x) = a [x - ( 1+ 2sqrt (3))] [ x - (1 - 2sqrt (3)) ] [ x - (3-sqrt (2))] [ x - ( 3 + sqrt (2)) ] =
(I used WolframAlpha to expand this )
a (x^4 - 8 x^3 + 8 x^2 + 52 x - 77)
Since f(0) = -154
Then
a (-77) = -154
a = -154/-77 = 2
So....the polynomial is
2 [ x^4 - 8 x^3 + 8 x^2 + 52 x - 77 ] =
2x^4 - 16x^3 + 16x^2 + 104x - 154
And we just need to add all the coefficients plus the constant term to get f(1) =
2 - 16 + 16 + 104 - 154 =
-48