+0  
 
0
58
5
avatar+397 

Let\(f(x) = \begin{cases} 9x+4 &\text{if }x\text{ is an integer}, \\ \lfloor{x}\rfloor+5 &\text{if }x\text{ is not an integer}. \end{cases} \)Find \(f(\sqrt{29})\)

 Apr 15, 2020
 #1
avatar+23689 
+2

welllll     sqrt29 is not an integer    so   f (sqrt29)   =   |_sqrt29_| +5  = 10

 Apr 15, 2020
 #2
avatar+397 
0

The wasn't right

qwertyzz  Apr 15, 2020
 #3
avatar+23689 
0

Well..... yes, it is ....according to your question....cheeky

ElectricPavlov  Apr 15, 2020
 #4
avatar+30087 
0

EP's answer to the question is correct!  If you think it isn't then you should say why you think that.  If you've just entered the result in some on-line set of questions and the response was that it was incorrect, it is possible that you haven't specified the question correctly here.

Alan  Apr 15, 2020
 #5
avatar+397 
0

Sorry.  I'll go reenter it.

qwertyzz  Apr 15, 2020

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