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# Let Find ​

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Let$$f(x) = \begin{cases} 9x+4 &\text{if }x\text{ is an integer}, \\ \lfloor{x}\rfloor+5 &\text{if }x\text{ is not an integer}. \end{cases}$$Find $$f(\sqrt{29})$$

Apr 15, 2020

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welllll     sqrt29 is not an integer    so   f (sqrt29)   =   |_sqrt29_| +5  = 10

Apr 15, 2020
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The wasn't right

qwertyzz  Apr 15, 2020
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Well..... yes, it is ....according to your question....

ElectricPavlov  Apr 15, 2020
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EP's answer to the question is correct!  If you think it isn't then you should say why you think that.  If you've just entered the result in some on-line set of questions and the response was that it was incorrect, it is possible that you haven't specified the question correctly here.

Alan  Apr 15, 2020
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Sorry.  I'll go reenter it.

qwertyzz  Apr 15, 2020