Let h(t) denote the height of an object in meters at time t seconds. h'(t) is the velocity of the object at time t seconds, and h''(t) = -9.8m/s^2 is the

Let h(t) denote the height of an object in meters at time t seconds. h'(t) is the velocity of the object at time t seconds, and h''(t) = -9.8m/s^2 is the acceleration of the object due to gravity. Suppose that at time t = 0, the height of the object is h(0) = h₀ and the velocity of the object is h'(0) = v₀. (Here, h₀ and v₀ are some constants.)

 

A. Find a formula for the velocity function h'(t) in terms of the constant v₀.