Let n be an odd integer with exactly 11 positive divisors. Find the number of positive divisors of \(8n^3\).
Thanks for any help.
8n^3 has 34 divisors.
n==3^10 ==59,049 ==(1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683, 59049)>>Total = 11 divisors.
8 * 59049^3 ==1,647,129,056,757,192==2^3 x 3^30
Number of divisors==[3 +1] x [30 + 1] ==4 x 31 ==124 divisors.
124 is correct. Thanks!
+46 
