Let $x$ and $y$ be integers satisfying $41x + 53y = 12$. Find the residue of $x$ modulo 53. (Express your answer as an integer from 0 to 52.)
Let x and y be integers satisfying 41x+53y=12. Find the residue of x modulo 53. (Express your answer as an integer from 0 to 52.)
If x=264 and y=−204 then 41x+53y=12. The residue of x(mod53)=52.